What fraction of chlorine will be precipitate | vedclass

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(B) The coordination compound $[CrCl(NH_3)_5]Cl_2$ dissociates in water to release the ions present outside the coordination sphere.The formula can be

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$2/3$

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(B) The coordination compound $[CrCl(NH_3)_5]Cl_2$ dissociates in water to release the ions present outside the coordination sphere.The formula can be written as $[CrCl(NH_3)_5]^{2+} + 2Cl^-$.When $AgNO_3$ is added,it reacts with the ionizable chloride ions: $2Cl^- + 2AgNO_3 \rightarrow 2AgCl(s) + 2NO_3^-$.Total chlorine atoms in the compound = $3$.Ionizable chlorine atoms = $2$.Therefore,the fraction of chlorine precipitated as $AgCl$ is $2/3$.

List-$I$ (Complex)	List-$II$ (Primary valency and Secondary valency)
$(A)$ $[Co(en)_2 Cl_2] Cl$	$(I)$ $3, 6$
$(B)$ $[Pt(NH_3)_2 Cl(NO_2)]$	$(II)$ $2, 4$
$(C)$ $Hg[Co(SCN)_4]$	$(III)$ $3, 4$
$(D)$ $[Mg(EDTA)]^{2-}$	$(IV)$ $2, 6$

What fraction of chlorine will be precipitated as $AgCl$ by using $AgNO_3$ from $[CrCl(NH_3)_5]Cl_2$?

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